How to File Upload using Ajax JQuery PHP 8 and MySQL?
Jun 07, 2022 . Admin
Hello Friends,
In this tutorial, you will learn How to Upload file using ajax jQuery PHP 8 and MySQL. This article goes in detailed on PHP 8 Upload & Store File in MySQL Tutorial. step by step explain ajax file upload php 8 Code Example. step by step explain simple file upload and store in php 8 mysql example. Let's see bellow example How to Insert Files into a MySQL Database Using PHP 8.
This article will give you simple example of How to Upload Files on Server in PHP 8.
So, let's see bellow solution:
index.php<!DOCTYPE html> <html lang="en"> <head> <title>How to File Upload using Ajax JQuery PHP 8 and MySQL</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script> </head> <body> <div class="container mt-5"> <div class="row"> <div class="col-md-12"> <div class="card m-auto w-75"> <div class="card-header text-center text-white bg-dark"> <h4>How to File Upload using Ajax JQuery PHP 8 and MySQL - Mywebtuts.com</h4> </div> <div class="card-body"> <div class="alert alert-success alert-dismissible" id="success" style="display: none;"> <button type="button" class="close" data-dismiss="alert">×</button> File uploaded successfully </div> <form id="submitForm"> <div class="form-group"> <label><strong>Select File : </strong><span class="text-danger"> *</span></label> <input type="file" class="form-control" name="file" id="file" multiple> <span id="error" class="text-danger"></span><br> </div> <div class="form-group d-flex justify-content-center"> <button type="submit" name="upload" class="btn btn-primary">Upload</button> </div> </form> </div> </div> </div> </div> </div> <script type="text/javascript"> $(document).ready(function(){ $("input").prop('required',true); $('#file').change(function () { var ext = this.value.match(/\.(.+)$/)[1]; switch (ext) { case 'txt': case 'pdf': case 'docx': case 'csv': case 'xlsx': $('#error').text(""); $('button').attr('disabled', false); break; default: $('#error').text("File must be of type txt,pdf,docx,csv,xlsx."); $('button').attr('disabled', true); this.value = ''; } }); $("#submitForm").on("submit", function(e){ e.preventDefault(); $.ajax({ url :"store.php", type :"POST", cache:false, contentType : false, // you can also use multipart/form-data replace of false processData : false, data: new FormData(this), success:function(response){ $("#success").show(); $("#success").fadeOut(2800); } }); }); }); </script> </body> </html>store.php
<?php if (isset($_FILES['file'])) { $file_name = $_FILES['file']['name']; $file_size = $_FILES['file']['size']; $file_tmp = $_FILES['file']['tmp_name']; $file_type = $_FILES['file']['type']; $servername = "localhost"; $username = "root"; $password = ""; $dbname = "tests"; $conn = mysqli_connect($servername, $username, $password, $dbname); if (!$conn) { die("connection failed:" .mysqli_connect_error()); echo "connection successfull"; } $sql="INSERT INTO posts(file) VALUES('$file_name')"; if ($conn->query($sql)===TRUE) { echo " "; }else{ echo "<h5 class='alert alert-primary'>Error :".$sql."<br>".$conn->error."</h5>"; } if (move_uploaded_file($file_tmp ,"uploads/".$file_name)) { echo "<h5 class='alert alert-primary'>File inserted Successfully!</h5>"; }else{ echo "<h5 class='alert alert-primary'>File Was Not inserted!</h5>"; } } ?>Output:
It will help you...